What is the combustion enthalpy of methane?
−890.8
Enthalpy of Combustion
| Substance | Combustion Reaction | Enthalpy of Combustion, ΔH∘c(kJmolat 25∘C) |
|---|---|---|
| methane | CH4(g)+2O2(g)⟶CO2(g)+2H2O(l) | −890.8 |
| acetylene | C2H2(g)+52O2(g)⟶2CO2(g)+H2O(l) | −1301.1 |
| ethanol | C2H5OH(l)+3O2(g)⟶2CO2(g)+3H2O(l) | −1366.8 |
| methanol | CH3OH(l)+32O2(g)⟶CO2(g)+2H2O(l) | −726.1 |
What is the enthalpy of combustion per mole of methane?
Molar Heat of Combustion (molar enthalpy of combustion) of Some Common Substances Used as Fuels
| Substance (fuel) | Molar Heat of Combustion (kJ mol-1) | ΔHreaction (kJ mol-1) |
|---|---|---|
| methane | 890 | ΔH = -890 |
| ethane | 1560 | ΔH = -1560 |
| propane | 2220 | ΔH = -2220 |
| butane | 2874 | ΔH = -2874 |
What is enthalpy combustion?
The enthalpy of combustion of a substance is defined as the heat energy given out when one mole of a substance burns completely in oxygen.
What is the change in enthalpy associated with the combustion of 530 g of methane CH4 )? Report your answer in scientific notation Your answer should?
What is the change in enthalpy associated with the combustion of 530 g of methane (CH4)? Report your answer in scientific notation. Your answer should have two significant figures. Use −890.8kJmol for the molar heat of combustion of methane.
What is the incomplete combustion of methane?
The incomplete combustion of methane can result in a slew of partially oxidized products, including CO, but also methanol, formic acid, formaldehyde, and higher hydrocarbons also.
Where is methane used for combustion?
The combustion of methane is used to obtain combustion gases, which provide energy to power gas turbines. In many places, methane is supplied to houses in pipes and used for heating and cooking.
What is r in enthalpy?
Standard enthalpy change of reaction, ΔH° First, notice that the symbol for a standard enthalpy change of reaction is ΔH°r. For enthalpy changes of reaction, the “r” (for reaction) is often missed off – it is just assumed. The “kJ mol-1” (kilojoules per mole) doesn’t refer to any particular substance in the equation.