## How do you find useful work in physics?

The work is calculated by multiplying the force by the amount of movement of an object (W = F * d). A force of 10 newtons, that moves an object 3 meters, does 30 n-m of work. A newton-meter is the same thing as a joule, so the units for work are the same as those for energy – joules.

**How do you find work Physics with time?**

Power is equal to work divided by time. In this example, P = 9000 J /60 s = 150 W .

### How do you find maximum work physics?

when the displacement is in the direction parallel to the application of force then the work done is said to be maximum. W=FscosΦ. Where Φ is the angle between force and displacement. If the force and displacement is in same direction then the work done on the body is maximum.

**What is the formula of work done?**

To express this concept mathematically, the work W is equal to the force f times the distance d, or W = fd. If the force is being exerted at an angle θ to the displacement, the work done is W = fd cos θ.

#### What is an example of useful work?

Some examples: Compression of a spring: (tension)(distance displaced from equilibrium) Expansion of a surface: (surface tension)(surface area increase) Expansion of a gas, commonly known as P-V work: (pressure)(change in volume)

**How do you solve work done problems in physics?**

Apply the work equation to determine the amount of work done by the applied force in each of the three situations described below.

- Diagram A Answer: W = (100 N) * (5 m)* cos(0 degrees) = 500 J.
- Diagram B Answer: W = (100 N) * (5 m) * cos(30 degrees) = 433 J.
- Diagram C Answer: W = (147 N) * (5 m) * cos(0 degrees) = 735 J.

## How do you solve work physics problems?

The formula for work is , work equals force times distance. In this case, there is only one force acting upon the object: the force due to gravity. Plug in our given information for the distance to solve for the work done by gravity. Remember, since the object will be moving downward, the distance should be negative.

**How do you find the work done by normal force?**

If ‘Normal Force’ means a force which is perpendicular to the surface (of intended motion) , the body will not move and the work done is Zero. If the force “F” is applied in an angle “alpha” to the surface, and the body moves a distance “L” along that surface, the work done would be: W=F*L*cos(alpha).

### What are the 3 formulas for work?

There are three key ingredients to work – force, displacement, and cause. In order for a force to qualify as having done work on an object, there must be a displacement and the force must cause the displacement.

**What are the three formula for work?**

Those three quantities are force, displacement and the angle between the force and the displacement. The work is subsequently calculated as force•displacement•cosine(theta) where theta is the angle between the force and the displacement vectors.

#### When we obtain useful work during a process?

When we obtain useful work during a process in which a finite system undergoes a change of state, when should that process terminate? Explanation: The process goes on until the system reaches the dead state. 2.

**What is the physics classroom?**

The Physics Classroom serves students, teachers and classrooms by providing classroom-ready resources that utilize an easy-to-understand language that makes learning interactive and multi-dimensional.

## What is the importance of studying physics in daily life?

Physics, or the study of matter, energy, and the interactions between them, helps us to understand the laws and rules that govern the physical world. Not every student will grow up and study physics on a deeper level, but everyone uses basic physics concepts to navigate everyday life.

**How do you find the work done by a force?**

Solution: The work done is calculated by using the formula: W = F × S. Here, Force F = 10 N. And, Distance, S = 1 m. So, Work done, W = 10 × 1 J. = 10 J. Thus, the work done is 10 joules. Example 2: Find the work done by a force of 10 N in moving an object through a distance of 2 m. Solution: Work done = Force × Distance moved.

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